AJAX - Send a Request To a Server
The XMLHttpRequest object is used to exchange data with a
server.
Send a Request To a Server
To send a request to a server, we use the open() and send() methods of the XMLHttpRequest object:
xmlhttp.open("GET","ajax_info.txt",true);
xmlhttp.send(); |
| Method |
Description |
| open(method,url,async) |
Specifies the type of request, the URL, and if the request should be handled asynchronously or not.
method: the type of request: GET or POST
url: the location of the file on the server
async: true (asynchronous) or false (synchronous) |
| send(string) |
Sends the request off to the server.
string: Only used for POST requests |
GET or POST?
GET is simpler and faster than POST, and can be used in most cases.
However, always use POST requests when:
- A cached file is not an option (update a file or database on the server)
- Sending a large amount of data to the server (POST has no size
limitations)
- Sending user input (which can contain unknown characters), POST is more
robust and secure than GET
GET Requests
A simple GET request:
Example
xmlhttp.open("GET","demo_get.asp",true);
xmlhttp.send(); |
View it » |
In the example above, you may get a cached result.
To avoid this, add a unique ID to the URL:
Example
xmlhttp.open("GET","demo_get.asp?t=" + Math.random(),true);
xmlhttp.send(); |
View it » |
If you want to send information with the GET method, add the information to the URL:
Example
xmlhttp.open("GET","demo_get2.asp?fname=Henry&lname=Ford",true);
xmlhttp.send(); |
View it » |
POST Requests
A simple POST request:
Example
xmlhttp.open("POST","demo_post.asp",true);
xmlhttp.send(); |
View it » |
To POST data like an HTML form, add an HTTP header with setRequestHeader().
Specify the data you want to send in the send() method:
Example
xmlhttp.open("POST","ajax_test.asp",true);
xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded");
xmlhttp.send("fname=Henry&lname=Ford"); |
View it » |
| Method |
Description |
| setRequestHeader(header,value) |
Adds HTTP headers to the request.
header: specifies the header name
value: specifies the header value |
The url - A File On a Server
The url parameter of the open() method, is an address to a file on a server:
| xmlhttp.open("GET","ajax_test.asp",true); |
The file can be any kind of file, like .txt and
.xml, or server scripting files like .asp and .php (which can perform
actions on the server before sending the response back).
Asynchronous - True or False?
AJAX stands for Asynchronous JavaScript and XML, and for the XMLHttpRequest
object to behave as AJAX, the async parameter of the open()
method has to be set to true:
| xmlhttp.open("GET","ajax_test.asp",true); |
Sending asynchronously requests is a huge improvement for web developers. Many of the tasks
performed on the server are very time consuming. Before AJAX, this operation could
cause the application to hang or stop.
With AJAX, the
JavaScript does not have to wait for the server response, but can instead:
- execute other scripts while waiting for server response
- deal with the response when the response ready
Async=true
When using async=true, specify a function to execute when the response is ready in the onreadystatechange event:
Example
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("myDiv").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","ajax_info.txt",true);
xmlhttp.send(); |
View it » |
You will learn more about onreadystatechange in a later chapter.
Async=false
To use async=false, change the third
parameter in the open() method to false:
| xmlhttp.open("GET","ajax_info.txt",false); |
Using async=false is not recommended, but for a few small requests this can be ok.
Remember that the JavaScript will NOT continue to execute,
until the server response is ready. If the server is busy or slow, the
application will hang or stop.
Note: When you use async=false, do NOT write an onreadystatechange
function - just put the code after the send() statement:
Example
xmlhttp.open("GET","ajax_info.txt",false);
xmlhttp.send();
document.getElementById("myDiv").innerHTML=xmlhttp.responseText; |
View it » |
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